cross-posted from: https://infosec.pub/post/789102

As Italy swelters under dangerous heat, McDonald’s workers called a strike after their air conditioning broke in oppressively hot kitchens.

  • pizzaiolo@slrpnk.net
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    1 year ago

    Thanks. Whenever I see Fahrenheit units I have no fucking idea of what the actual temperature is meant to be

    • SteefLem@lemmy.world
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      1 year ago

      Yeah i know what u mean, and since the article is about italie which uses celcius its even weirder :)

    • I_Miss_Daniel@kbin.social
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      1 year ago

      One helpful tip I’ve figured out. 100 foreignheight is body temperature. So if it’s around 100°F it’s around 38°C.

    • PaleRider@feddit.uk
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      1 year ago

      So the proper conversion from Celsius to Fahrenheit is F = 9/5C + 32

      But an easy way to do it (roughly) from Celsius to Fahrenheit is double it and add 30.

      To convert from Fahrenheit to Celsius is subtract 30 then halve it.

    • Blaubarschmann@feddit.de
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      1 year ago

      A little helper to get a feel for it: 20°C is 68°F, 25°C is 77°F, 30°C is 86°F etc. Meaning, you just remember one or two combinations and then for every 5°C change it’s 9°F up or down

    • Resonosity@lemmy.ca
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      1 year ago

      I think about the difference between the two using differences instead of absolutes. That looks like this:

      It’s kind of hard to do this calc:

      F = [ (9/5) * C ] + 32

      Or this one:

      C = (5/9) * (F - 32)

      I refer to those as absolute equations. You have to take into account the pesky offset everytime you want to convert. What if we drop it? This makes:

      F = (9/5) * C = 1.8 * C

      C = (5/9) * F ~= 0.6 * F

      I refer to those as relative or difference equations because if you subtract a temperature from the other, you get the same thing:

      F1 = [ (9/5) * C1 ] + 32

      F2 = [ (9/5) * C2 ] + 32

      F2 - F1 = [ (9/5) * C2 ] + 32 - { [ (9/5) * C1 ] + 32 }

      = [ (9/5) * C2 ] - [ (9/5) * C1 ] + 32 - 32

      = [ (9/5) * C2 ] - [ (9/5) * C1 ]

      = (9/5) [ C2 - C1 ]

      F2 - F1 = (9/5) (C2 - C1)

      F = (9/5) ∆C

      So, why is this useful?

      Say you have a temperature in Celsius and want to go to Fahrenheit. Simply multiply that number in your head by 1.8 (or think of this as multiplying by 180° as in trig) and finally add to 32. So, 1 °C is (1 * 1.8) + 32 °F or about 34 °F.

      Going the other way is a little bit weirder. I make approximations when going the other way by thinking of 180° and how that can be divided. So, 180°, 90°, 45°, etc. corresponds to 1.8 °F (1 °C), 0.9 (0.5 °C), 0.45 °F (0.25 °C), etc. I also approximate by choosing the nearest multiple of 5 or 10 °C (9 or 18 °F). So, 44 °F is between 41 °F (5 °C) and 50 °F (10 °C), closer to 41. It’s off by 3, which is about 3.6, which is 2 in Celsius world. This means 44 °F is about 7 °C.

      Hope you get the gist! Celsius really is better. I remember this in a pinch:

      10 °C = 50 °F

      20 °C = 68 °F

      30 °C = 86 °F

      40 °C = 104 °F

      50 °C = 122 °F

      Etc.

      The freezing temps are a little hard since you cross zero into negatives, but the extrapolation can help